In the neutral mononuclear iridium(III) title compound, [Ir(C(8)H(7)ClNO)(C(11)H(8)N)(2)], the Ir(III) atom adopts an octa-hedral geometry, and is coordinated by two 2-phenyl-pyridyl ligands and one anionic 4-chloro-acetanilide ligand. The 2-phenyl-pyridyl ligands are arranged in a cis-C,C' and cis-N,N' fashion. Each 2-phenyl-pyridyl ligand forms a five-membered ring with the Ir(III) atom. The 2-phenyl-pyridyl planes are perpendicular to each other [dihedral angle = 89.9 (1)°]. The Ir-C and Ir-N bond lengths are comparable to those reported for related iridium(III) 2-phenyl-pyridyl complexes. The remaining two coordination sites are occupied by the amidate N and O atoms, which form a four-membered ring with the iridium atom (Ir-N-C-O). The amidate plane is nearly perpendicular to both 2-phenyl-pyridyl ligands [dihedral angles = 87.8 (2) and 88.3 (2)°].